More > JRiver Media Center 30 for Windows
NEW: Alexa in MC30
cncb:
It is not an Alexa device that can just be discovered. Even with Ring, I have to first connect my Ring account by typing in my account details, and then the devices are "discovered" by Alexa. That's basically what we are talking about here.
dtc:
The real problem is the access code and the whole low, cap nomenclature. It's kind of like asking for a serial number in an awkward format. Hopefully you can fix that.
Thanks.
kevin_marchant:
--- Quote from: JimH on September 13, 2022, 12:47:40 am ---You have to separate J and Talk a little when you speak. Alexa often mistakes what I say for another skill whose name is at all similar other than it starts with a J. Speak loudly also.
--- End quote ---
Thanks Jim, Craig.
It now works most of the time if I leave a 2 second pause between "J" and "Talk" so the problem is with my speaking and not your end. However, it'd suggest that it's a bit unruly as a wake phrase. I wonder if you had set it as JAYTALK if you wouldn't need the pause between the "J" and the "Talk"
cncb:
--- Quote from: kevin_marchant on September 13, 2022, 04:31:35 pm ---It now works most of the time if I leave a 2 second pause between "J" and "Talk" so the problem is with my speaking and not your end. However, it'd suggest that it's a bit unruly as a wake phrase. I wonder if you had set it as JAYTALK if you wouldn't need the pause between the "J" and the "Talk"
--- End quote ---
Weird. Mine always detects it no problem even if I purposely try to have no pause. Maybe you have something with a similar name installed (or Alexa likes my mumbly voice)?
maliceme:
I'm getting "Cannot authenticate on M C Server" from my Alexa device. (It successfully launches JTalk, but when I give a command - Play Pink Floyd - I get the cannot authenticate message.)
I've been careful to follow the capa lowb process. In the Alexa app, I get a confirmation: Access key is {MyAccessKey}, User name is {bob}, Password is {x} characters, Connection is {http}. I note that my password is actually x+1 characters, but repeated attempts to set this value always returns a message that "Password is {x} character".
Any help is appreciated.
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