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Author Topic: Expressions: Most efficient way to do a logic "OR" with CONTAINS-like function?  (Read 1491 times)

Quixote

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Expressions: Most efficient way to do a logic "OR" with CONTAINS-like function?
« on: June 15, 2015, 04:25:30 pm »
I'm wanting to do a check on lyrics for Explicit content. (I know I can also do this using a Search list, however, I need to do this as an expression.)

Questions:
  • What is the best practice way for searching a list of words/phrases in a tag?
  • Is MATH( | ) the appropriate way to do an "OR" in an expression?
  • Would a regular expression perform better or be more flexible?

What I've come up with so far is to identify "witch" and " ass " in Lyrics:

Code: [Select]
=If(Math(IsEqual([Lyrics],witch,8)|IsEqual([Lyrics],/ ass/ ,8))
    ,explict
    ,clean)

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glynor

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Re: Expressions: Most efficient way to do a logic "OR" with CONTAINS-like function?
« Reply #1 on: June 15, 2015, 05:49:41 pm »
Assuming you really mean within the Expression Language, see:
http://wiki.jriver.com/index.php/Expression_Language#Conditional_Functions
and
http://wiki.jriver.com/index.php/Boolean_Operations

The Search Language, however, supports OR type operations directly:
http://wiki.jriver.com/index.php/Search_Language#Grouping_and_Combining
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ferday

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Re: Expressions: Most efficient way to do a logic "OR" with CONTAINS-like function?
« Reply #2 on: June 15, 2015, 06:12:32 pm »
Probably regex

ifelse(regex([lyrics]/#(witch|ass)/b)#/,0,0),explicit,clean)

Note: I'm learning regex so I've probably missed something, haven't tested...but you can extend the (1|2|3|...) ad infinite
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mark_h

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Re: Expressions: Most efficient way to do a logic "OR" with CONTAINS-like function?
« Reply #3 on: June 16, 2015, 01:35:17 am »
If you want to more deeply explore timing of operations you can turn on logging and create your expressions, then run each and check how long they take to run in the log... you can then choose the most optimal...
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